Pivot occupations in hackerrank select a,b,c,d from ( select name,occupation,dense_rank()over(partition by occupation order by name) rnk from occupations) sorce pivot(max(name) for occupation in ('Doctor' as a,'Professor' as b,'Singer' as c,'Actor' as d)) vis order by rnk; HackerRank personal solutions. This repository contains solutions to all the HackerRank SQL Practice Questions - HackerRank-SQL-Challenges-Solutions/Advanced Select/Occupations. We create columns for each occupation (Doctor, Professor, Singer, Actor), and for each row number (rn), we pick the name that belongs to the respective occupation and place it in the corresponding column. community/OVER ([PARTITION BY columns] [ORDER BY columns])https://learnsql. Create a HackerRank account Be part of a 23 million-strong community of developers. The PIVOT operation: Takes the source_tb table as input. Please read our cookie policy for Pivot the Occupation column in OCCUPATIONS so that each Name is sorted alphabetically and displayed underneath its corresponding Occupation. The output column Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. (SELECT * FROM ( SELECT NAME,OCCUPATION, rank() OVER(partition by occupation order by OCCUPATION,name) rn FROM OCCUPATIONS ) PIVOT (MAX(NAME) FOR OCCUPATION IN ('Doctor' as a,'Professor' as b,'Singer' as c,'Actor' Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. Code: Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. if you will just write name it won't work. If you do not include the row_number() you will just print one row of data. Please read our cookie policy for I was just wondering if we can write PIVOT without any aggregate function, I was struggling with the same initially and adding RowNum did the trick. Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. Blog; Check GroupBy Solution for same question here :https://www. Jenny Ashley Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. So in advance; I'm sorry if this is too basic stuff or my query is too messy. 0 Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. In this HackerRank Functions in SQL problem solution, Pivot the Occupation column in OCCUPATIONS so that each Name is sorted alphabetically and displayed underneath its corresponding Occupation. sql at master · raleighlittles/HackerRank-SQL Pivot the Occupation column in OCCUPATIONS so that each Name is sorted alphabetically and displayed underneath its corresponding Occupation. You basicly create an CTE that includes the OCCUPATIONS table plus an added ID column, this is needed for sorting the results correctly, this is the CTE I called KEYED_OCCUPATIONS. Please read our cookie policy for This part is necessary to build the dummy columns for the pivot. with temp as (select* ,ROW_NUMBER() OVER (PARTITION BY occupation ORDER BY name) AS id from OCCUPATIONS ) , pvt_temp as (select * From temp pivot (max(name) for occupation in (Doctor, Professor, Singer, Actor) )as pvtCols )select Doctor, Professor, Singer, Actor from pvt_temp HackerRank: [SQL Advanced Select] (3/5) OCCUPATIONS | pivot, set, case, when, order by, group by in SQL. Please read our cookie policy for In this part of the query, we use conditional aggregation to pivot the data. When somebody else want to run on some other editor. `PIVOT (MAX(Name) FOR Occupation IN ([Doctor], [Professor], [Singer], [Actor]) ) AS t_pivot;` This is the part where the pivot is being built. number() over (PARTITION BY occupation ORDER BY name) AS rownum, occupation as occ FROM occupations ) AS s PIVOT ( MIN(name) FOR occ IN (Doctor, Professor, Singer, Actor) ) AS pvt; 3 | Parent I agree to HackerRank's Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. (PARTITION BY Occupation ORDER BY Name) rn, Name, Occupation FROM Occupations ) AS source PIVOT (MAX(Name) FOR occupation IN ([Doctor],[Professor],[Singer],[Actor])) as pvt ORDER BY rn Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. ==== Steps 1 ==== select name, Doctor, Professor, Singer, Actor from occupations pivot (count (occupation) for occupation in (Doctor, Professor, Singer, Actor)) as p Out put: Aamina 1 0 0 0 Ashley 0 1 0 0 Belvet 0 1 0 0 Britney 0 1 0 0 Christeen 0 0 1 0 Eve 0 0 0 1 Jane 0 0 1 0 Jennifer 0 0 0 1 Jenny 0 0 1 0 Julia 1 0 0 0 Ketty 0 0 0 1 Kristeen Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. com/blog/sql-over Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. " Pivot the Occupation column in OCCUPATIONS so that each Name is sorted alphabetically and displayed underneath its corresponding Occupation. OVER (PARTITION BY OCCUPATION ORDER BY NAME) AS RowNum FROM OCCUPATIONS) AS PivotTable PIVOT (MAX(NAME) FOR OCCUPATION IN (Doctor, Professor, Singer, Actor) ) AS PivotTableAlias ORDER BY Pivot the Occupation column in OCCUPATIONS so that each Name is sorted alphabetically and displayed underneath its corresponding Occupation. I wrote a query but it didn't work. My SQL Server solution, using PIVOT and CTE :-WITH Name) Rown from Occupations t) Pivot (min (name) for Occupation in (' Doctor ' Doctor, ' Professor ' Professor, ' Singer ' Singer, ' Actor ' Actor)) order by Rown; *(A little simplified version) In the subquery part I've numerated the rows in every Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. The output column My Oracle Solution using the Pivot function: Key things here, this solution is really about Pivot and row_number: Pivot requires you to use an aggregate function, so you have wrap a function like max or min around name. hackerrank. It is still not being working out. ( SELECT ROW_NUMBER() OVER (PARTITION BY OCCUPATION ORDER BY NAME) ROW_ID,NAME,OCCUPATION FROM OCCUPATIONS ) AS TF PIVOT ( MAX(NAME) FOR OCCUPATION IN ([Doctor],[Professor],[Singer],[Actor]) ) PV. be/7C8wlTNUQzAinput an integer Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. The result of the PIVOT operation is stored in the pv table. (PARTITION BY Occupation ORDER BY Name) AS RowNum FROM Occupations ) AS X ) AS Y PIVOT ( MAX(Name) FOR Occupation IN ([Doctor], [Professor], [Singer], [Actor]) ) AS PVT; First, I have changed the MAX() funtion to Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. Ok | Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. Sample Output. AS R, NAME, OCCUPATION FROM OCCUPATIONS. Pivot the Occupation column in OCCUPATIONS so that each Name is sorted alphabetically and displayed Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. The output column headers should be Doctor, Professor, Singer, and Actor, respectively. The output column headers should be Doctor, Professor, Pivot the Occupation column in OCCUPATIONS so that each Name is sorted alphabetically and displayed underneath its corresponding Occupation. For anyone who doesn't know MS SQL Server, the brackets are just for naming. Please read our cookie policy for Annotated solutions to HackerRank's SQL domain questions. com/dev. WITH PIVOT AS (SELECT. over (partition by occupation order by name) as rank FROM OCCUPATIONS ) PIVOT ( MAX(Name) FOR occupation IN ('Doctor' as Doctor,'Professor' as Professor,'Singer' as Singer,'Actor' as Actor) ) ORDER BY 1,2,3,4; try thi Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. Problem Statement: Pivot the Occupation column in OCCUPATIONS so that each Name is sorted alphabetically and displayed underneath its corresponding Occupation. The output column headers should be Doctor, Professor, Singer, and Actor, Pivot the Occupation column in OCCUPATIONS so that each Name is sorted alphabetically and displayed underneath its corresponding Occupation. But,When I written down on HackerRank platform. OVER(PARTITION BY Occupation ORDER BY Name) AS Row_Numer FROM Occupations; SELECT Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. Source: HackerRank. Table: 'OCCUPATIONS' HackerRank practice exercise for Pivoting in MySQL - nborbas/SQL_Pivoting_Practice_HackerRank. Sample queried records: R Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. Please read our cookie policy for more information about how we use cookies. the fish! your code is being run down. The output column headers should be Doctor, "Learn to pivot the Occupation column in OCCUPATIONS table on HackerRank SQL, sorting Names alphabetically under Doctor, Professor, Singer, and Actor headers. Pivot the Occupation column in OCCUPATIONS so that each Name is sorted alphabetically and displayed underneath its corresponding Occupation. by Akshay Daga (APDaga)-March 02, 2021. sql at main · Pavith19/HackerRank-SQL-Challenges-Solutions /* Pivot the Occupation column in OCCUPATIONS so that each Name is sorted alphabetically and displayed underneath its corresponding Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. AS rn FROM Occupations We get the following output: Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. WITH RankedOccupations AS ( -- Assign a row number to each name based on their occupation and sort them alphabetically SELECT Name, Occupation, ROW_NUMBER() OVER (PARTITION BY Occupation ORDER BY Name) AS RowNumber FROM OCCUPATIONS ) -- Pivot the table by occupations SELECT Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. com/watch?v=tCjXUAeJoDsCopy code from here:https://dev19community. [Singer], [Actor] from( SELECT Name, Occupation from Occupations as sourcetable Pivot(Max(Name) for Occupation in([Doctor], [Professor], [Singer], [Actor]))) as pivottable. (SELECT NAME,OCCUPATION,ROW_NUMBER() OVER(PARTITION BY OCCUPATION ORDER BY NAME) AS RN FROM OCCUPATIONS) SELECT Doctor,Professor,Singer,Actor FROM (SELECT RN,Doctor,Professor,Singer,Actor WITH cte AS ( SELECT * FROM ( SELECT RANK() OVER (PARTITION BY occupation ORDER BY name) AS rank, occupation, name FROM occupations) AS oc_n PIVOT ( MAX(name) FOR occupation in (Doctor,Professor, Singer , Actor) ) AS pivot_table) Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. Group by ranking; Use case to create each column (Doctor, Professor, Singer, and Actor) Use an aggregation function to include the cases in the SELECT statement There is only one value per group so its not relevant whether it is min or max. It depends on your strategy to solve a problem, if you choose to interact with chat-gpt to find a good solution that's great, but I think chat-gpt will refers you dynamic queries or some ways like my query because there is no pivot operator like Microsoft SQL Server in MySQL. - HackerRank-SQL/Occupations. HackerRank SQL Interview Question: Level Medium. The output column headers should be Doctor, Professor Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. Hi Naresh,u can use the following query using pivot. You dont need to add quotes for occupations in pivot statement- SELECT Doctor, Professor, Singer , Actor from ( SELECT name,occupation ,row_number() over (partition by occupation order by name ) as rn from occupations Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. In the solution below we need a subquery to extract the data where we informed the fields the will became our data and columns, and after a row number, this last its necessary because the pivot functions need an aggregation function, how we are working with strings the only function that work is MAX, however this function bring only the max Pivot the Occupation column in OCCUPATIONS so that each Name is sorted alphabetically and displayed underneath its corresponding Occupation. blogspot. please help me solve this problem: You are given a table, containing two columns: column is one of the followings: Doctor Professor Singer Actor Write a query to output the names underneath the Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. Please signup or login in HackerRank-AdvancedSelect-Occupations - pivot, row_number 1 minute read Occupations - pivot, row_number. youtube. We use cookies to ensure you have the best browsing experience on our website. pivot is a structure that changes some row data into a column, that's why I had pivoted "FOR OCCUPATION IN ([Doctor], [Professor], [Singer], [Actor]) " and in a pivot you aways passes a aggregation function, for text Pivot the Occupation column in OCCUPATIONS so that each Name is sorted alphabetically and displayed underneath its corresponding Occupation. The output column headers should be doctor, professor, singer, and actor, respectively. 0. com/challenges/occupationsLearn: Buil Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. Otherwise, we can't build all of the columns. Pivot occupations. Pivot the Occupation column in OCCUPATIONS so that each Name is sorted alphabetically and displayed underneath its corresponding Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. Pivot the Occupation column in OCCUPATIONS so that each Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. Please read our cookie policy for Please follow us https://www. I do not what is being happening over there in Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. Pivot the Occupation column in OCCUPATIONS so that each Name is sorted alphabetically and displayed underneath its corresponding Occupation. instagram. SELECT * FROM (SELECT ROW_NUMBER OVER (PARTITION BY OCCUPATION ORDER BY NAME) AS RN, OCCUPATION, NAME FROM OCCUPATIONS GROUP BY OCCUPATION, NAME) AS OC PIVOT (MAX (NAME) FOR Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. Please read our cookie policy for . Professor, Singer, Actor FROM ( SELECT name, occupation FROM occupations order by occupation, name) PIVOT (MIN(name) FOR occupation IN ('Doctor' as Doctor,'Professor' as Professor, 'Singer' as Singer, 'Actor' as Actor Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. The goal is to transform the data, from one data format into a different str Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. SELECT DOCTOR, PROFESSOR, SINGER, ACTOR FROM ( SELECT ROW_NUMBER() OVER (PARTITION BY OCCUPATION ORDER BY NAME) RowNum, NAME, OCCUPATION FROM OCCUPATIONS Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. The output column headers should be Doctor, Professor, Singer, and Actor, respectively Occupations. The output column headers should be Doctor, Professor, Singer, and Actor, respectively. Contribute to rene-d/hackerrank development by creating an account on GitHub. because in the syntax of PIVOT you have to use a aggregation function so you have a choice to you max/min function on name. https://www. (PARTITION BY Occupation ORDER BY Name) AS RowNum--Para ordenar alfabeticamente FROM Occupations ) SELECT [Doctor] as Doctor, [Professor] as Professor, [Singer] as Singer, [Actor] as Actor FROM RankedNames PIVOT ( Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. Pivot the occupation column in occupations so that each Name is sorted alphabetically and displayed underneath its corresponding Occupation. Why do I need RowNumber and PartitionBy MS SQL Code: SELECT Doctor, Professor, Singer, Actor FROM ( SELECT Name, Occupation, ROW_NUMBER() OVER (PARTITION BY Occupation ORDER BY Name) as rn FROM Occupations ) AS src_table PIVOT ( MAX(Name) FOR Occupation IN (Actor, Doctor, Professor, Singer) ) AS pvt_table ORDER BY rn; Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. For each occupation (Doctor, Professor, Singer, Actor), it takes the MAX(name) value and places it in the corresponding column. Hackerrank occupations problem link. Step 3: Select the columns and order the results Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. Pivots the data, transforming the occupation column values into individual columns. The output column Pivot the Occupation column in OCCUPATIONS so that each Name is sorted alphabetically and displayed underneath its corresponding Occupation. occupation, ROW_NUMBER() OVER ( PARTITION BY Occupation ORDER BY Name) as row from occupations) occup pivot (min(name) for occupation in ([Doctor], [Professor] ,[Singer],[Actor])) as pivottable; 0 | Permalink. Please read our cookie policy for Occupations contain four occupation types: Doctor, Professor, Singer and Actor. The output column headers should be Doctor, Professor, A lesson that teaches you how to solve the following problem from the SQL section in HackerRank. Here is my work; Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. com/2022/09/oc This approach is easy to use and understandable. ( SELECT OCCUPATION, NAME, ROW_NUMBER() OVER (PARTITION BY OCCUPATION ORDER BY NAME) RankTable FROM OCCUPATIONS ) RT PIVOT ( MIN (NAME) FOR OCCUPATION IN ([Doctor], [Professor], [Singer], [Actor]) ) PV. Please read our cookie policy for Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. CASE WHEN occupation = 'Doctor' THEN name END AS Doctor, CASE WHEN occupation = 'Professor' THEN name END AS Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. Note: Print NULL when there are no more names corresponding to an occupation. Previous Video Links: program to read two numbers from the keyboard and display the larger value on the screen: https://youtu. I'm new to sql and this community. Anyway, I think solution is to pivot the data. 19. mbb zaqsa cybybw tmwi kikah rifne gkh ojpagk pjygfk kbrng